Starting restoration of this Colnago C96.
Just arrived from Netherlands. Rabobank team paint scheme.
If you start seeing these errors it means your server or instance started running out of kernel memory.
[10223.291166] java: page allocation failure: order:0, mode:0x1080020(GFP_ATOMIC), nodemask=(null) [10223.301794] java cpuset=/ mems_allowed=0-1 [10223.307211] CPU: 29 PID: 19395 Comm: java Not tainted 4.14.154-99.181.amzn1.x86_64 #1 [10223.315658] Hardware name: Xen HVM domU, BIOS 4.2.amazon 08/24/2006 [10223.322004] Call Trace: [10223.325230] <IRQ> [10223.328193] dump_stack+0x66/0x82 [10223.332213] warn_alloc+0xe0/0x180
In particular, these Order 0 (zero) errors, mean there isn’t even a single 4K page available to allocate.
This might sound weird on a system were we have a lot of RAM memory available. And actually, this may be a common situation on systems where the kernel is not tuned up properly.
In particular, we need to look at the following kernel parameter:
min_free_kbytes: This is used to force the Linux VM to keep a minimum number of kilobytes free. The VM uses this number to compute a watermark[WMARK_MIN] value for each lowmem zOn one in the system. Each lowmem zone gets a number of reserved free pages based proportionally on its size. Some minimal amount of memory is needed to satisfy PF_MEMALLOC allocations; if you set this to lower than 1024KB, your system will become subtly broken, and prone to deadlock under high loads. Setting this too high will OOM your machine instantly.
On systems with very large amount of RAM memory, this parameter is usually set too low. Change default value (have a look to the previous paragraph to avoid too low or too high values) and restart with sysctl. 1GB is the value I use on most of the large memory servers (64GB+).
sudo sed -i '${s/$/'"\nvm.min_free_kbytes = 1048576"'/}' /etc/sysctl.conf
sysctl vm.min_free_kbytes
echo "reloading the settings:"
sudo /sbin/sysctl -p
Starting the restoring process on this Eddy Merckx Corsa-01.
The symbols to the left of the BB cover (“technical”) are divided into 3 categories:
The symbols to the right of the BB cover (“statistical”) form a serial number, it consists of a letter and a set of digits. A letter means another series of frames, a number is another frame in the series (001-9999). The exception is the production from 1980 (there is no letter, and in the prototypes even digits, and there are just over 1000 of them).
E – 1981-1984
Z – 1984-1986
A – 1986-1988
B – 1988-1990
C – 1990-1991
D – 1992-1993
F – 1994-1995
G – 1996-1998
H – 1998-2000
J – 2001-2002
K – 2002-2004
L – 2004-2006
P – 2006-2008
In addition to such markings, there are unusual ones:
CS – Capri Sonne
ED – Europ Decor
W – Winning ?
KE – Kelme
HL186P – Hans Lubberding 1986 Pista (Panasonic) and similar – his teammates
https://www.retrobike.co.uk/threads/eddy-merckx-decoding-for-everyone.410031/
Are you looking for new challenges?
At Project Kuiper we are working to provide broadband internet service to tens of millions of people around the world who are currently underserved. Come join us!
Do you want to know more about this project? have a look to this video:
Here are some of our current openings. Feel free to reach out directly to me if you want to know more about these or other positions.
Senior Systems Development Engineer
Senior Ecad Tools Application Engineer
I just wanted to write a couple lines/guidance on this regard as this is a recurring question when configuring storage, not only in the cloud, but can also happen on bare metal servers.
Throughput is the measure of the amount of data transferred from/to a storage device per time unit (typically seconds).
The throughput consumed on a volume is calculated using this formula:
IOPS (IO Ops per second) x BS (block size)= Throughput
As example, if we are writing at 1200 Ops/Sec, and the chunk write size is around 125Kb, we will have a total throughput of about 150Mb/sec.
This is important because we have to be aware of the Maximum Total Throughput Capacity for a specific volume vs the Maximum Total Instance Throughput.
Because, if your instance type (or server) is able to produce a throughput of 1250MiB/s (i.e M4.16xl)) and your EBS Maximum Throughput is 500MiB/s (i.e. ST1), not only you will hit a bottleneck trying to write to the specific volumes, but also throttling might occur (i.e. EBS on cloud services).
Here is documentation about Maximum Instance Throughput for every instance type on EC2: https://docs.aws.amazon.com/AWSEC2/latest/UserGuide/ebs-optimized.html
And here about the EBS Maximum Volume throughput: https://docs.aws.amazon.com/AWSEC2/latest/UserGuide/ebs-volume-types.html
If we have an instance/server that has more throughput capabilities than the volume, just add or split the storage capacity into more volumes. So the load/throughput will be distributed across the volumes.
As an example, here are some metrics with different volume configurations:
1 x 3000GB – 9000IOPS volume:
3 x 1000GB – 3000IOPS volume:
Look at some of the metrics: these are using the same instance type (m4.10xl – 500Mb/s throughput), same volume type (GP2 – 160Mb/s throughput) and running the same job:
Entering final on KTIW (Tacoma Narrows Airport) with Cessna 172P
Some time ago I was given the opportunity to be the curator/keeper/custodian of this historic car.
I like to think that, even if you own a car like this, your goal is to take care of it, and pass it along to the next generations when the time comes.
235,147 Chevrolet Camaros were produced in 1968. This Original SS is one of only 12,496 L48 SS Camaros produced that year, which represents only 5% of total 1968 Camaro production.
She was born on Thursday, Jun 13th, 1968 at the Norwood’s GM plant in Cincinnati, Ohio.
According to the original warranty booklet with protect-o-plate, she was delivered to Joe O’Brien Chevrolet in Cleveland, OH, and the first owner on a Saturday, Jun 29th, 1968, also in Ohio.
She is a True SS, All matching numbers, equipped with the following factory options:
Walk through and start up video (start up at 2:49):
Hernan Vivani's Blog 